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数学
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求不定积分∫(x^2-2x-4)dx
人气：432 ℃ 时间：2020-05-28 14:27:07
解答
∫(x^2-2x-4)dx=∫x^2dx-∫2xdx-∫4dx=1/3x^3-x^2-4x +k
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