某质点的运动方程是S=t-(2t-1)的平方,则t=1是的瞬时速度为
人气:365 ℃ 时间:2019-08-22 14:28:27
解答
解由S=t-(2t-1)^2
即S=t-(4t^2-4t+1)
即S=-4t^2+5t-1
求导得S'=-8t+5
由位移的导数为速度函数
知v=-8t+5
知t=1时,v=-8+5=-3.为什么5t的导数是5(5t)'=5(t)'=5×1=5.
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