y=x/(x^2+3)y'=[(x^2+3)-x*2x]/(x^2+3)^2=-(x^2-3)/(x^2+3)^2=-(x+√3)(x-√3)/(x^2+3)^2=0x1=-√3,x2=√31.x1=-√3,函数在x1的左边导数小于0,右边大于0取极小值y(-√3)=-√3/62.x2=√3因为函数是奇函数,利用对称性...