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cos60°+sin45°×cos45°-tan60°×tan30°=?
cos45°-cos60°分之1+sin30°分之1+cos²30°+sin²45°=?
3tan30°+cot45°+cos30°+2sin60°-2tan45°=?
人气:438 ℃ 时间:2020-04-16 04:28:21
解答
cos60°+sin45°×cos45°-tan60°×tan30°=1/2+(√2)/2×(√2)/2-√3×(√3)/3=1/2+1/2-1=0cos45°-cos60°分之1+sin30°分之1+cos²30°+sin²45°=(√2)/2-2+2+3/4+1/2=(2√2)/4+3/4+2/4=(2√2+5)/43tan...
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