∫ (1 - x)²/√x dx= ∫(1 - 2x + x²)/√x dx= ∫ x^(- 1/2) dx - 2∫ x^(1/2) dx + ∫ x^(3/2) dx= x^(1 - 1/2)/(1 - 1/2) - 2x^(1 + 1/2)/(1 + 1/2) + x^(1 + 3/2)/(1 + 3/2) + C= 2√x - 2 * 2/3 * x^(...