sinθcos24+cosθsin24=cos24cosθ+sin24sinθsinθ(cos24-sin24)=cosθ(cos24-sin24)显然cos24-sin24≠0所以sinθ=cosθtanθ=sinθ/cosθ=1tan(θ+60)=(tanθ+tan60)/(1-tanθtan60)=(1+√3)/(1-√3)=-2-√3...