回答：这个问题属于“指数分布”问题.其均值μ为μ = ∫{0,∞}tP(t)dt = ∫{0,∞}t 0.02e^(-0.02t)dt = 1/0.02 = 50 (h).其方差σ²为σ² ＝ ∫{0,∞}(t-μ)^2 P(t)dt = 1/0.02^2 = 2500 (h^2)....