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数学
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2(3a^2b+2a-5b)-3(4a-b+a^2b),其中a=4;b=-3
人气:361 ℃ 时间:2019-10-19 23:25:39
解答
2(3a^2b+2a-5b)-3(4a-b+a^2b)
=6a^2b+4a-10b-12a+3b-3a^2b
=3a^2b-8a-7b
当a=4, b=-3时
原式=3×16×(-3)-8×4-7×(-3)
=-144-32+21
=-155
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