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试证:对任意的正整数n,有
1
1×2×3
+
1
2×3×4
+…+
1
n(n+1)(n+2)
1
4
人气:480 ℃ 时间:2020-09-18 05:07:41
解答
证明:∵
1
n(n+1)(n+2)
=
1
2
[(
1
n
-
1
n+1
)-(
1
n+1
-
1
n+2
)],
1
1×2×3
+
1
2×3×4
+…+
1
n(n+1)(n+2)
=
1
2
[(1-
1
2
)-(
1
2
-
1
3
)]+…+
1
2
[(
1
n
-
1
n+1
)-(
1
n+1
-
1
n+2
)]=
=
1
2
[(1-
1
2
)-(
1
n+1
-
1
n+2
)]<
1
4
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