> 数学 >
已知x^2-4xy+5y^2-6y+9=0,求((x+y+3)/(x-y+1))的值
人气:150 ℃ 时间:2020-03-28 04:04:17
解答
x^2-4xy+5y^2-6y+9=0
(x^2-4xy+4y^2)+(y^2-6y+9)=0
(x-2y)^2+(y-3)^2=0
y-3=0
y=3
x-2y=0
x=6
(x+y+3)/(x-y+1)
=(6+3+3)/(6-3+1)=3
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版