若m^2+n^2-m-4n+4/1/4=0,求m^n-mn的值_数学解答

若m^2+n^2-m-4n+4/1/4=0,求m^n-mn的值

人气：422 ℃　时间：2020-03-28 12:52:29

解答

m^2+n^2-m-4n+4/1/4=0
(m^2-m+1/4)+(n^2-4n+4)=0
(m-1/2)^2+(n-2)^2=0
m=1/2
n=2
m^n-mn=1/4-1=-3/4