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函数f(x)有一阶导数,则limf(2+ln(t-1))/ln(t-1)=?
人气:126 ℃ 时间:2019-08-20 21:27:28
解答
直接用洛必达法则
lim[t->t0] f(2+ln(t-1))/ln(t-1)
=lim[t->t0] {f'(2+ln(t-1))*1/(t-1)}/{1/(t-1)}
=lim[t->t0] f'(2+ln(t-1))
=f'(2+ln(t0-1))
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