化简求值 已知|2a-b+1|+(3a+ 3/2 b)²=0、求代数式 b²/a+b ÷(a/a-b -1 )x (a - a² /a
说明:b²/a+b 就是 a+b分之b平方
求的代数 b² /(a+b) ÷{a /(a-b) -1 }x {a - a² /(a+b) } 的值
人气:225 ℃ 时间:2019-10-14 06:53:45
解答
所谓的对白1:∵|2a-b+1|+(3a+3/2b)²=0且|2a-b+1|≥0,(3a+3/2b)²≥0∴2a-b+1=0,3a+3/2b=0解得a=-1/4,b=1/2∴[b²/(a+b)]÷[a/(a-b)-1]×[a-a²/(a+b)]=[b²/(a+b)]÷[...
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