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若a∈【0,2π】,且根号(1-sin2a)=根号2* (a-π/4),则a取值范围?
人气:101 ℃ 时间:2020-05-08 15:09:08
解答
sin2a=1-根号2*(a-π/4)2sina*cosa=sin²a+cos²a-根号2*(a-π/4)(sina-cosa)²=根号2*(a-π/4)1/2sin²(a-π/4)=根号2*(a-π/4)sin²(a-π/4)=2根号2*(a-π/4)a∈【0,2π】,(...
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