a³+2a²+2a+1=0a³+1+2a(a+1)=0(a+1)(a²-a+1)+2a(a+1)=0(a+1)(a²-a+1+2a)=0(a+1)(a²-a+1)=0a²-a+1=(a-1/2)²+3/4>0所以 a+1=0a=-1a^2012+a^2013=1-1=0 若有帮助请采纳 嘻嘻...