直线y=4x+a的斜率为4,y=4x+a和y=x^3-2x^2+3相切,则切线的斜率必为4.对曲线方程y=x^3-2x^2+3求导,使其导数为4,dy/dx=3x^2-4x=4,3x^2-4x-4=0,即(3x+2)(x-2)=0,解得x=2,x=-2/3,切点的横坐标为2或-2/3,将x=2,x=-2/3分别...