答：x+x^2+1/x+1/x^2=4(x^2+2+1/x^2)+(x+1/x)-6=0(x+1/x)^2 +(x+1/x)-6=0(x+1/x +3) (x+1/x -2)=0解得：x+1/x=-3,则x^2+3x+1=0所以：x=(-3±√5)/2或者：x+1/x=2x^2-2x+1=0x=1经检验,x=1或者x=(-3±√5)/2都是原分式...