(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)等于多少?
人气:357 ℃ 时间:2020-04-18 18:04:40
解答
思路:在原式乘上(2-1),不断的产生平方差,可以巧解.(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1) 原式=(2-1)(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1) =(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16...
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