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求证:sin^2α+cosαcos(π/3+a)-sin^2(π/6-α)的值是与α无关的定值
人气:428 ℃ 时间:2020-09-14 08:54:36
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sin^2α+cosαcos(π/3+a)-sin^2(π/6-α)
=(sinα)^2+cosα[1/2×cosα-√3/2×sinα]+[1/2×cosα-√3/2×sinα]^2
=(sinα)^2+1/4×(cosα)^2-3/4×(sinα)^2
=1/4×(sinα)^2+1/4×(cosα)^2
=1/4
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