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三角函数 sin7/5pai*cos(-11/6pai)+tan(-15/4pai)*tan7/5pai
人气:227 ℃ 时间:2020-10-02 02:34:29
解答
化简三角函数:原式=sin(π+2π/5)*cos[-(π+5π/6)]+tan[-(4π+π/4)]*tan(π+2/5π). =-sin(2π/5)cos(5π/6)-tan(π/4)*tan(2π/5). =-sin(2π/5)*[-cos(π/6)]-1*tan(2π/5). =(√3/2)sin(2π...
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