您好：原式=[x/(x-1)²-1/(x-1)]*（x²-1）/2=1/2[x/(x-1)²-1/(x-1)]*(x+1)(x-1)=1/2[x(x+1)/(x-1)-(x+1)]=(x²+x-x²+1)/2(x-1)=(x+1)/2(x-1)如果本题有什么不明白可以追问,如果满意记得采...