计算:
(1)
+− (2)
+
(3)(
-
)÷
(4)
÷(a+1)-
.
人气:284 ℃ 时间:2020-05-15 04:42:20
解答
(1)原式=2xy+x(x−y)+y(x+y)x2−y2=(x+y)2(x+y)(x−y)=x+yx−y;(2)原式=2a−(a+2)(a+2)(a−2)a−2(a+2)(a−2)=1a+2;(3)原式=x2+2xx−1•x−1x=x(x+2)x−1•x−1x=x+2;(4)原式=2(a+1)a−1•1a+1-(a+1)(a−...
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