(x+3)/(x+2)=1+1/(x+2) (x+4)/(x+3)=1+1/(x+3) (x+5)/(x+4)=1+1/(x+4) (x+2)/(x+1)=1+1/(x+1) 则原式可化简为1/(x+2)+1/(x+3)=1/(x+4)+1/(x+1),两边通分得（2x+5）/（x+2)(x+3)=（2x+5）/（x+1)(x+4) 若x＝-2.5,则原式成立； 当x不等于-2.5,则（x+2)(x+3)=（x+1)(x+4) 展开,方程无意义 则x＝-2.5