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分解因式:(xy-1)的平方+(x+y-2)(x+y-2xy).
人气:339 ℃ 时间:2020-03-28 15:24:23
解答
(xy-1)^2+(x+y-2xy)(x+y-2)
=(xy-1)^2+4xy+(x+y)^2-2(xy+1)(x+y)
=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)
=(x+1)^2(y+1)^2
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