> 数学 >
x^2+10x+20=0
解一元二次方程
人气:443 ℃ 时间:2020-07-16 13:01:52
解答
x^2+10x+20
= x^2+10x+ 25 - 5
= (x+5)^2 - 5 = 0
(x+5)^2 = 5
x+5 = ±√5
x= -5 ±√5不好意思,输错了,是x^2+10x+21=0那就更简单了。
x^2+10x+21
= x^2+10x+ 25 - 4
= (x+5)^2 - 4 = 0
(x+5)^2 = 4
x+5 = ±2
x= -5 ±2
x1 = -3, x2 = -7
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版