9.03*10^23个氨分子中含有＿摩尔质子,＿个电子
这种题应该怎么算?请写出具体过程,
人气：134 ℃ 时间：2019-08-18 22:34:19
解答
1NA=6.02*10^23个则9.03*10^23=1.5NA=1.5mol而1molNH3分子中有10mol质子所以1.5molNH3中有15mol质子电子和质子数量是一样的也是15mol如果问个数就是15*6.02*10^23=9.03*10^24个补充:N是7号元素有7个质子,H是1号有1个...
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