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初二因式分解(x-y)²+4(x-y+1)最后是什么?
人气:199 ℃ 时间:2020-04-05 01:28:34
解答
答:
(x-y)²+4(x-y+1)
=(x-y)²+4(x-y)+4
=(x-y)²+2*2(x-y)+2²
=(x-y+2)²
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