题目不完整吧,x没有范围吗
g(x)=2sin^2x+√3sin2x+m^2
=1-cos2x+√3sin2x+m^2
=√3sin2x-cos2x+m^2+1
=2sin（2x- π/6）+m^2+1x属于R继续做如果x属于R，g(x)<3恒成立因为sin（2x- π/6）∈[-1,1]g(x)的最大值 是 m²+3 ≥3故 m 无解