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化简:1/2x-1/(x+y).[(x+y)/2 - (2x²+2xy)/2x]
人气:470 ℃ 时间:2020-05-30 22:26:03
解答
原式=1/2x-1/(x+y).[(x+y)/2- (x+y)/2]
=1/2x-1/(x+y).0
=1/2x(2x²+2xy)/2x ≠ (x+y)/2,应该是:x+y
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