化简 sinx+sin(x+2π/3)+cos(x+5π/6)
人气:353 ℃ 时间:2020-09-06 14:49:36
解答
原式=sinx+(sinxcos2π/3+cosxsin2π/3)+(cosxcos5π/6-sinxsin5π/6)
=sinx+(-1/2)sinx+(√3/2)cosx+(-√3/2)cosx-(1/2)sinx
=0
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