解
y=ln²(1-2x)
y'=dy/dx=[ln²(1-2x)]'
=2ln(1-2x)[ln(1-2x)]'(1-2x)'
=2ln(1-2x)[1/(1-2x)(-2)
=[-4ln(1-2x)]/(1-2x)
微分
dy=[-4ln(1-2x)]/(1-2x)dx