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将标有“6V,3W”、“6V,6W”的甲、乙两个灯泡,串联接在9V的电源上,它们的实际功率分别是______ W和______ W.
人气:467 ℃ 时间:2019-08-21 21:12:05
解答
(1)灯泡电阻R1=
U21
P1
=
(6V)2
3W
=12Ω,R2=
U22
P2
=
(6V)2
6W
=6Ω;
(2)两灯泡串联时,电路电流I=
U
R1+R2
=
9V
12Ω+6Ω
=0.5A;
(3)灯泡实际功率P1实=I2R1=(0.5A)2×12Ω=3W,
P2实=I2R2=(0.5A)2×6Ω=1.5W;
故答案为:3;1.5.
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