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(37*38*39*40)+1的算术平方根
人气:180 ℃ 时间:2020-05-23 18:39:01
解答
√[(37*38*39*40)+1]
=√[37*(37+1)*(37+2)*(37+3)+1]
=√[37*(37+3)*(37+1)*(37+2)+1]
=√[(37^2+3*37)*(37^2+3*37+2)+1]
=√[(37^2+3*37)^2+2(37^2+3*37)+1]
=√(37^2+3*37+1)^2
=37^2+3*37+1
=37*(37+3)+1
=37*40+1
=1480+1
=1481
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