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计算:9^[log3(2)]-2[1+0.5log2(5)]
人气:435 ℃ 时间:2020-05-26 12:43:38
解答
9^[log3(2)]-2[1+0.5log2(5)]
=[3^log3(2)]^2-2[log2(2)+log2(5^0.5)]
=2^2-2[log2(2*5^0.5)]
=4-log2[2*5^0.5]^2
=4-log2(20)
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