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化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
人气:305 ℃ 时间:2020-04-21 02:44:29
解答
sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)
=(-sinα)*(-sinα)+(-cosα)*(-cosα)
=(sinα)^2+(cosα)^2=1
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