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解方程:√3*(x²-x)=√2*(x²+x)过程详细点,
人气:152 ℃ 时间:2020-01-27 12:33:24
解答
√3*(x²-x)=√2*(x²+x)
√3*x*(x-1)=√2*x*(x+1)
1.x=0
2.x0时 √3*(x-1)=√2*(x+1)
(√3-√2)x=√2+√3
x=(√2+√3)/(√3-√2)
=(√2+√3)^2
=5+2√6
所以x=0 或 x=5+2√6
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