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计算:[4(x-2)*2+12(x+2)(x-2)-8(x-1)*2(x-2)]·4(x-2)
速求 越简便越好
人气:238 ℃ 时间:2020-05-21 22:34:00
解答
[4(x-2)^2+12(x+2)(x-2)-8(x-1)^2(x-2)]-4(x-2)
=4(x-2)[x-2+3(x+2)-2(x-1)^2-1]
=4(x-2)(x-2+3x+6-2x^2+4x-2-1)
=(4x-8)(-2x^2+8x+1)
=-8x^3+32x^2+4x+16x^2+64x-8
=-8x^3+48x^2+68x-8
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