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计算 根号下11····1-22·····2 .其中11····1有2n个,22·····2有n个(n是正整数)
人气:426 ℃ 时间:2019-11-13 20:55:37
解答
记x=111.1有n个1
则:
根号下11····1-22·····2 .其中11····1有2n个,22·····2有n个
=根号下(x*10^n -x)-2x
=根号下x(10^n -1)
=根号下x*999...9有n个9
=根号下9x^2
=3x
=333.3有n个3
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