函数y=根号下（x^2+1）+1 (x_数学解答

函数y=根号下（x^2+1）+1 (x

人气：307 ℃　时间：2019-12-21 06:53:32

解答

y=√（x^2+1）+1>2
=> (y-1)^2 =x^2+1
=>x^2=(y-1)^2-1
=>x=-√[(y-1)^2-1]
=>x=-√[(y-1)^2-1]
=>y=-√[(x-1)^2-1] (x>2)