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y=sin(90°+x)cos(30°-x)最大值
人气:336 ℃ 时间:2020-06-12 06:53:02
解答
y=sin(90°+x)cos(30°-x)
=cosxcos(30°-x)
=1/2[cos30°+cos(2x-30°)]
=1/2[√3/2+cos(2x-30°)]
所以
最大值=1/2[√3/2+1]
=√3/4+1/2
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