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x^2*x^8+x^13/x^3 a^19/(a^12/a^3) (x-2y)^5/(2y-x)^3 (x-y)^5/(x-y) (x-y)^6/(y-x)^4 (x-2y)^6/(2y-x)^3
人气:168 ℃ 时间:2020-02-03 08:08:27
解答
x^2*x^8+x^13/x^3 =2x^10
a^19/(a^12/a^3)=1
(x-2y)^5/(2y-x)^3=-(x-2y)^2
(x-y)^5/(x-y) =(x-y)^4
(x-y)^6/(y-x)^4=(x-y)^2
(x-2y)^6/(2y-x)^3=(2y-x)^3
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