答：三角形ABC中：C-A=π/2C=A+π/2所以：sinC=sin(A+π/2)=cosAcosC=cos(A+π/2)=-sinA因为：sinA*[cos(C/2)]^2+sinC*[cos(A/2)]^2=(3/2)sinB所以：sinA*(cosC+1)+sinC*(cosA+1)=3sinBsinAcosC+cosAsinC+sinA+cosA=...