根据题意,有
已知:EF=5,FG=1.5,tanBEA=1/2,BE‖GC
求:CD.
BE‖GC => ∠BEA=∠GCF => tanGCF=1/2
FC=2GF=3 => EC=EF+FC=8
GF/CD=EF/EC => CD=GF*EC/EF=1.5*8/5=2.4
根据题意,有
已知:EF=5,FG=1.5,tanBEA=1/2,BE‖GC
求:CD.
BE‖GC => ∠BEA=∠GCF => tanGCF=1/2
FC=2GF=3 => EC=EF+FC=8
GF/CD=EF/EC => CD=GF*EC/EF=1.5*8/5=2.4