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已知sin(3π+α)=2sin(3/2π+α),则(sina-4cosa)/(5sina+2cosa)
人气:224 ℃ 时间:2020-06-03 00:23:03
解答
sin(3π+a)=2sin(3π/2+a),左边=sin(3π/2+3π/2+a)=sin(3π/2)cos(3π/2+a)+sin(3π/2+a)cos(3π/2)=-cos(3π/2+a)=cos(π/2+a)=-sina右边=2sin(3π/2+a)=-2sin(π/2+a)=-2cosa所以-sina=-2cosatana=2(sina-4cosa)/...
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