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求证 (cos^6 x )+ (sin^6 x) = 1 -3sin^2 x + 3sin^4 x
写下左右过程.
人气:432 ℃ 时间:2020-10-02 04:43:53
解答
证:(cos^6 x )+ (sin^6 x) =[(cos^2 x )]^3+ [(sin^2 x)]^3 =[(cos^2 x )]+ [(sin^2 x)]*[ [(cos^4 x )-[(cos^2 x )(sin^2 x)+[(sin^4x)]=1*{[(cos^2 x )+ (sin^2 x)]^2-3(cos^2x) (sin^2 x) }=1-3(cos^2x) (sin^2 x...
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