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有几道计算题要简算
2002/200220022003
893536*78
24*1953+19*2953
人气:489 ℃ 时间:2020-06-12 05:05:38
解答
2002/200220022003
=2002/(200220022002+1)
=1/((200220022002+1)/2002)
=1/(100010001+1/2002)
=9.999*10^(-9)
893536*78
=893536*(100-22)
=89353600-893536*22
=69695808
24*1953+19*2953
=24*1953+19*(1953+1000)
=(24+19)*1953+19000
=43*1953+19000
=102979
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