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数学
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Find the equation of the tangent line at x=2 for f(x)=√((4x+1)/(5x-1))
100分题,
人气:107 ℃ 时间:2020-03-28 21:37:33
解答
定义域为D={x|x=1/5}
导数f'(x) =-9/[2*(5x-1)²*√((4x+1)/(5x-1)) ]
f'(2)=-1/18
f(2)=1
在点(2,1),函数的切线的斜率为-1/18,切线方程为 y-1=-1/18 *(x-2)
整理,得 x+18y -20=0
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