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y=x除以根号下x^2+1的微分.
人气:348 ℃ 时间:2020-03-28 07:26:56
解答
dy=d(x/√(x^2+1))
={√(x^2+1)*dx-x*2x/[2√(x^2+1)]dx}/(x^2+1)
=1/(x^2+1)^(3/2)*dx
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