log(16)(27)=ln(27)/ln(16)=3ln3/4ln2=a
ln3=4a/3*ln2
log(6)(16)
=ln16/ln6
=4ln2/(ln2+ln3)
=4ln2/(ln2+4a/3*ln2)
=12/(4a+3)请问这步log(16)(27)=ln(27)/ln(16)=3ln3/4ln2=a 到ln3=4a/3*ln2这步是怎么来的？能不能写清楚点呢？