ag SO4^2-物质的量 = a/96 molAl2(SO4)3中Al3+与SO4^2-物质的量之比 = 2:3所以原溶液中Al3+物质的量 = a/96 * 2/3 = a/144 mol把此溶液取一半,则取出的溶液中Al3+物质的量 = (a/144)/2 = a/288 mol加水稀释至2VmL,则...